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Novice Joined: 20 Nov 2001 Posts: 35 Location: USA

This is probably a really simple question, but I have trouble none-the-less.

I'm trying to get one IF statement to differentiate between cases.

Basically, on 2d6, if the number rolled is a 2, 3, 4, 9, 10, 11, 12, I want it to one thing.
If it's a 5, 6, 7, 8 I want it do something else.

Now logically, in my mind, I'd just do something like this:

#IF (@DTotal=2 | 3 | 4 | 9 | 10 | 11 | 12) {Do true} {Do false, in this case, 5, 6, 7, 8}

then go on my merry way.

But it seems to think that it's true reguardless of the number rolled.

If I substitute & in there, it always thinks it's false, so I restructured the if to look like this.

#IF (@DTotal = 2 | 3 | 4 & 5 & 6 & 7 & 8 | 9 | 10 | 11 | 12) {Do this}

But again, that didn't work.

I don't really want to make an if for all 11 numbers, so could anybody shed some light on this? Maybe I just dunno the difference between logical and bitwise functions... one of the many things I was never taught in public school. hehe.

Anyways, thanks guys.

-Crymson

GURU Joined: 23 Dec 2000 Posts: 4834 Location: USA

Umm, try this:

#if (@DTotal >= 5 AND @DTotal <= 8) {#Noop here's where the 5 through 8 code goes} {#noop here is where the other code goes}

li'l shmoe of Dragon's Gate MUD

Novice Joined: 20 Nov 2001 Posts: 35 Location: USA

That worked. Sometimes, the answer is so freakin simple.

Thanks

-=Crymson

Reality is the effect of alcohol deficiency