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shalimar
GURU
Joined: 04 Aug 2002
Posts: 4690
Location: Pensacola, FL, USA
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 Posted: Sat Sep 29, 2007 6:08 am
[2.04] $local #loop
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#LOOP 25 {#ADD $test 1;#SAY $test}
The value of $test is always 1.
Shouldn't it increment itself since it is completely within the loop? |
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Tech
GURU
Joined: 18 Oct 2000
Posts: 2733
Location: Atlanta, USA
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Posted: Sat Sep 29, 2007 8:30 am
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I think this is the way it's supposed to be. Since $test is defined with the scope of the loop ( and only withing that scope ) it is essentially reset with every iteration. It is the same as declaring a variable with a 'while' in C/C++/Java, it's redefined at the start of each loop iteration and destroyed at the end of each loop iteration. You need a variable outside of the loop to do what you want.
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Fang Xianfu
GURU
Joined: 26 Jan 2004
Posts: 5155
Location: United Kingdom
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Posted: Sat Sep 29, 2007 1:27 pm
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Tech is correct.
#local $test
#loop 25 {#add $test 1;#say $test}
gives you the result you're looking for. |
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