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Stevestones01
Beginner
Joined: 25 May 2010
Posts: 14
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 Posted: Wed Jun 02, 2010 3:11 am
assigning a variable to a variable
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I'm not sure if this is even possible, but I have a variable with a list of targets in it and I have another variable called @temp_target. What I want it to do is check if the target 'priest' is in the list of targets, if it is, replace 'priest' with the value in @temp_target. Here is the code I'm using.
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#IF (@elderly_priest_count=1 AND @temp_target!=0) {
#IF (%item( @target_list, 1)="priest") {
%item( @target_list, 1) = @temp_target
}
}
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when I check the syntax it says there is an unmatched bracket at where the equal sign is in the third line of code. Also, I know this code is only checking to see if the first item in the variable is 'priest'. Is there any way to check if it's anywhere in the list at one time? And if it is, find out what position in the list it's at? Thanks in advance. |
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MattLofton
GURU
Joined: 23 Dec 2000
Posts: 4834
Location: USA
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Posted: Wed Jun 02, 2010 3:20 am
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1)when I check the syntax it says there is an unmatched bracket at where the equal sign is in the third line of code.
Can't start a line with %, nor can you use a function as the "a" in a=b syntax. If you want to use a function to draw out a string value representing a variable name, you will need to use #VARIABLE.
2)Is there any way to check if it's anywhere in the list at one time? And if it is, find out what position in the list it's at?
Check out %ismember(). It returns the element number, or 0 if it's not a member of the list. |
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Stevestones01
Beginner
Joined: 25 May 2010
Posts: 14
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Posted: Wed Jun 02, 2010 3:47 am
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thanks for the quick answer. It helped alot 
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