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chamenas
Wizard
Joined: 26 Mar 2008
Posts: 1547
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 Posted: Mon Mar 22, 2010 8:28 pm
%match question
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It says here that if no match is found, it returns 0. However, if it does find a match, the variables that go in the latter parts of the parameters gain values, but what does the function return? I'm hoping it returns true for an #IF statement. However, if it doesn't, would #IF (!%match(blah)) work just as well?
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Rahab
Wizard
Joined: 22 Mar 2007
Posts: 2320
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Posted: Mon Mar 22, 2010 8:48 pm
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That help page says:
| Quote: |
| If it matches, the position of the match in the string is returned (starting with 1). |
Thus, it returns a positive integer if it matches, and an #if will count that as TRUE. |
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chamenas
Wizard
Joined: 26 Mar 2008
Posts: 1547
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Posted: Mon Mar 22, 2010 8:53 pm
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Yes, I noticed that. I'm an idiot. I came here to post, but you're very quick and efficient. Thank you.
Edit: Sadly, I'm having other errors with it. *sighs* |
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chamenas
Wizard
Joined: 26 Mar 2008
Posts: 1547
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Posted: Mon Mar 22, 2010 8:59 pm
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| Code: |
#switch (%params)
(%ismember(%params, @c_name)) {
$_mem_num = %ismember(%params, @c_name)
$_lvl = %item(@c_lvl, $_mem_num)
$_class = %item(@c_class, $_mem_num)
$_rank = %item(@c_rank, $_mem_num)
$_clan = %item(@c_clan, $_mem_num)
$_clan_color = @clancolor(@c_clan, $_mem_num)
$_is_brackets = @isbrackets(@c_clan, $_mem_num)
#show %if($_is_brackets, "[ ", "( ")%ansi($_clan_color)$_clan%if($_is_brackets, " )", " ]")" ["$_lvl" "$_class"] "%params" ("$_rank")"
}
("all") {
$_num_items = %numitems(@c_name)
#say "Listing off all current names, this will be spammy..."
#say $_num_items " entries."
#wait 500
$_curr_item = 1
#loop $_curr_item,$_num_items {
#say $_curr_item". "%item(@c_name, $_curr_item)
$_curr_item = $_curr_item + 1
#wait 200
}
}
{
$_max_iter = %numitems(@c_name)
$_is_match = 0
$_iteration = 1
#LOOP $_iteration, $_max_iter {
$_curr_char = %item(@c_name, $_curr_iter)
#IF (%match($_curr_char, %params))
{
#show "Partial match found for "%params
$_is_match = 1
$_curr_iter = $_max_iter
}
{
$_curr_iter = $_curr_iter + 1
}
}
#IF ($_is_match)
{
#exec {find $_curr_char}
}
{
#say "Could not find "%params
#say "Make sure the name is spelled correctly, or try 'find all' to get a listing of the names."
}
}
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All I get is: Illegal Character in Expression
I tried adjusting the #IFs and the #LOOP to no avail. I found if I delete this entire section:
| Code: |
#LOOP $_iteration, $_max_iter {
$_curr_char = %item(@c_name, $_curr_iter)
#IF (%match($_curr_char, %params))
{
#show "Partial match found for "%params
$_is_match = 1
$_curr_iter = $_max_iter
}
{
$_curr_iter = $_curr_iter + 1
}
}
#IF ($_is_match)
{
#exec {find $_curr_char}
}
{
#say "Could not find "%params
#say "Make sure the name is spelled correctly, or try 'find all' to get a listing of the names."
}
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It compiles fine, so it must be in here. Removing any or both of the #IF statements does nothing. Nor does changing the #LOOP to static numbers. Nor does any of the syntax formatting that I tried. |
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chamenas
Wizard
Joined: 26 Mar 2008
Posts: 1547
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Posted: Mon Mar 22, 2010 9:45 pm
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Apparently I cant put a space between the comma and the next variable in a loop..
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Zugg
MASTER
Joined: 25 Sep 2000
Posts: 23379
Location: Colorado, USA
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Posted: Tue Mar 23, 2010 6:18 am
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Nope, you can't. Always remember that CMUD uses Spaces as delimiters between arguments when using any #command.
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