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emnaki
Wanderer
Joined: 12 May 2007
Posts: 59
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 Posted: Thu Jan 24, 2008 11:42 am
reading user input in a LUA script
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I can't seem to figure out how to get the user input via LUA in C-MUD, I've tried the below function:
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function getinput()
print("Enter part:")
input = io.stdin:read()
print(input.." received")
end
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But it does not seem to work. Is it even possible to do it? |
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Larkin
Wizard
Joined: 25 Mar 2003
Posts: 1113
Location: USA
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Posted: Thu Jan 24, 2008 1:02 pm
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You could make a call to the CMUD prompt command, maybe?
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Arminas
Wizard
Joined: 11 Jul 2002
Posts: 1265
Location: USA
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Posted: Thu Jan 24, 2008 2:22 pm
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For a single parameter use: zs.param() or zs.param(number of the parameter that you want) or zs.param(-1) to get all of them.
For multiple parameters use: zs.params() to get them all or zs.params(n) to get all of them starting at position n or if you want to be contrary zs.params(-n) to get only the one at position n.
In my opinion the best way to pull out the parameters into a usable form is to place them into a table using the following.
local list = {}
for i=1, zs.numparam do
list[i]=zs.param(i)
end
Edit: I misread the question sorry.
At the moment I am thinking that you create an oninput trigger that you turn on from within the lua function.
Something like.
#oninput {(*)} {#noinput;input=%1}
Then use zs.var.input() in your script. Sorry I'm in a hurry cannot go into it further. Perhaps Fang already knows how to do this strait from within Lua sans the trigger. |
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Arminas, The Invisible horseman
Windows 7 Pro 32 bit
AMD 64 X2 2.51 Dual Core, 2 GB of Ram |
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Fang Xianfu
GURU
Joined: 26 Jan 2004
Posts: 5155
Location: United Kingdom
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Posted: Thu Jan 24, 2008 5:05 pm
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Why me? :(
But yeah, I do. io.read() won't work because the command line isn't linked to stdin, but you can use zs.func.prompt() in exactly the same way, like Larkin suggested.
something = zs.func.prompt()
The only way to get stuff from the command line is with an oninput trigger - you can use Lua code in the trigger script itself. |
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