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Wanderer Joined: 05 Sep 2008 Posts: 53

There is a handy time script written in LUA that would allow me to translate game times into real time...and I have no background in LUA and learned most of my scripting from reading the CMUD manual...so I am trying to see if I can get some help successfully using the script....or maybe some help understanding the math behind it so I can translate the entire script into zScript.

the script can be found at https://github.com/missionz3r0/Dartmud-Lua-Scipts/blob/eae80bcb25bd4ab5649492482bae53ae3933efa7/Scripts/date.lua

Here is an example line to trigger from, the date reading [Month Day, Year].

106 [Vio 12, 1696] Too weak to lift it? Hire me!

so if I wanted the script to take [Vio 12, 1696] and output somthing like [1/1/2001], how would i need to configure the trigger?

thank you for your time :)

Posted: Wed May 03, 2023 3:36 am

You should be able to just stick all of that inside a #LUA command.

Search the help system for 'lua' to see how to reference CMUD variables inside the code.

As for your closing question... I have no clue which month number Vio is supposed to be. You would need to make your own reference table to convert that.

Apprentice Joined: 03 Jul 2006 Posts: 110

That program doesn't appear to do what he wants to do. From my (very limited) understanding of the code, it takes a time (in seconds as far as I can tell, though I can't say what the zero reference is) and calculates a "reckoning" date based on the length the chosen system's day, month, and year in seconds. To translate the opposite way, you would need to determine the dating system, presumably from the month name ("vio" is the 7th month out of an 8 month Thorpian year, with each month being 4 "Earth" days and a year being 32 days), and then calculate the number of seconds that have elapsed from the baseline per the date listed. It doesn't seem that cmud has a function to return a date based on elapsed time entered, however, so a system would need to be created to determine the number of days passed (including perhaps the irregular adding of "leap seconds") and using that to calculate the current date, including the adding of a leap day every 4 years.

Mike