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That's interesting because I don't think there are any such restrictions with the #LOG command. Granted the #LOG command is a little more limited with what you can write, can't exactly write a binary ...

Start with using zMUD. CMUD is still a beta software in heavy development. Secondly, what you are describing are called "triggers" and you should read the help files regarding that. Then come to the z ...

I talked with Zugg about this earlier and you should get something once the public package system has been properly tested. That is when we have a protocol that works and is stable.

This was a whil ...

You can use the "scroll lock" key as well as Ctrl+Z

Search is a wonderful tool...

CMUD is being written using the themed-components that were created as part of the zApp project. This means that CMUD will support skins/themes.

CMUD will support t ...

Bah to late but here is my solution using two functions (also works from base 2 to 36):
#FUNC dec2any {%if( "%1"!="0", %concat( @dec2any(%eval(%1/%2),%2&# ...

One thought... Since the security model in Vista has changed and Microsoft is actually trying to encourage users to run under a limited account. You might want to reconsider putting all files in the C ...

It's part of zMapper, or rather it's part of the scripting options that you get when having zMapper as a plugin in zMUD.

The only way I know of is via zMapper and the zMUDLink object.

The "Submit a Request for Assistance" seems like a good idea. For the future though maybe you should tie it to the forum accounts (so that the name and email is taken care of automatically if availabl ...

Well, it was a *long* If all goes well, I'll release it around 11am Monday morning (Mountain time, which means 10am Pacific, 1pm Eastern US).
This will be a very interesting week for sure but what ti ...

Ok, last question then: Whenever I do something with an account,- in this case change it to 0,- is there any way I can put that in a separate external textfile? Like a log of some sorts?
Sure there i ...

Just using the first trigger/cond combo doesn't do much since all it does is to reset the variable capturing citizens and then activating the trigger that capture new citizens (trigger nr 2).
So you ...

Your pattern has regex syntax, use this:
#REGEX {H:(\d+) M:(\d+) <([a-z- -]+)>} {#echo hrm}

Now, the question is, how to get the zone names listed in there?
Fantasizing (13863) - Fantasy Fields
By using the functions %zonename and %roomzone. For example change the loop in the above script ...

Hmm, very easy actually. The first alias (search_color) works right out of the bat since it doesn't use they %map function.

#ALIAS room_current {#ECHO Color in %roomname( ) ~(%room ...

#ECHO %roomname( %map.SelectRoomID) ~(%map.SelectRoomID~) have %map.CurRoom.NumLinks links
This will display the name, id and number of links in the current room.
For help on the com ...

#TRIGGER {^Citizens of the City of Mercinae.$} {#var citizens "";#t+ capture_citizens}
#COND {^The City of Mercinae has %d citizens.$} {#t- capture_citize ...

Using blank settings and issuing the following commands works without a hitch
#VAR mob_types %array("dog","cat","bird")
#ALIAS kk {kill %1}
kk %arrg ...

Is the identifier passed on to the kk alias always one word consisting only of a-z chars? If it contains spaces, commas or other chars then must you surround the identifier with appropriate delimiters ...

Nah, but it substitutes the entire pattern which is not always what you want to do and thus we also have PSUB.

#alias search_color {
#VARIABLE map_rooms {%mapquery( %concat( "[Color] = ", %1, " AND ZoneID = ", %zonenum))}
#ECHO {Searched for c ...

You can do it simpler than that:
#TRIGGER {naughty word} {#SUB ""}

What exactly are you trying to do? zMUD can filter stuff just fine, I just don't understand what you are up to... It does sound like you are looking for a substitution trigger or am I completely off b ...

Does it handle defaults, for example can I do this?
#FUNCTION add($a,$b=34) ($a+$b)
thus only having to provide $a when calling the function unless I want to provide both $a and $b